30x^2+20x-30=0

Solution for 30x^2+20x-30=0 equation:

30x^2+20x-30=0

a = 30; b = 20; c = -30;
Δ = b2-4ac
Δ = 202-4·30·(-30)
Δ = 4000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4000}=\sqrt{400*10}=\sqrt{400}*\sqrt{10}=20\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20\sqrt{10}}{2*30}=\frac{-20-20\sqrt{10}}{60}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20\sqrt{10}}{2*30}=\frac{-20+20\sqrt{10}}{60}
$